
1.SQL 걷기반 퀘스트 42번 문제
https://nbc-spring-6g-precamp.oopy.io/17a2dc3e-f514-81a7-89ab-ef2a4e51d58d
[작성한 쿼리]
SELECT d.name
FROM employees e left join departments d on e.department_id=d.id
WHERE e.name=null
[정답쿼리]
SELECT d.name
FROM departments d LEFT JOIN employees e ON d.id = e.department_id
WHERE e.id IS NULL;
2.SQL 걷기반 퀘스트 46번 문제
https://nbc-spring-6g-precamp.oopy.io/17a2dc3e-f514-817c-8908-e508f900aaad
[작성한 쿼리]
select p.name, sum(o.quantity) as cum_quantity
from products p inner join orders o on p.id=o.product_id
group by p.name
)a
order by cum_quantity desc limit 1
[정답쿼리]
SELECT p.name, SUM(o.quantity) AS total_quantity
FROM products p INNER JOIN orders o ON p.id = o.product_id
GROUP BY p.id
ORDER BY total_quantity DESC LIMIT 1
